20. Median completed order amount
Asked in screens shaped like: Capital One, JPMorgan, Robinhood
Report the median completed order amount without a percentile function. The median is the middle value for an odd count and the average of the two middle values for an even count, so the solution has to handle both.
Requirements
- Columns: median_amount
- Only status = 'completed'
- Exactly one row
- median_amount rounded to 2 decimals
Expected output
median_amount
Row order is not graded on this problem.
Tables this problem reads. The full warehouse is available in thesandbox.
orders
~200 rows
Order headers. One row per order, so amount is the order total — not a line total.
- order_idINTEGER— 1000–1199
- customer_idTEXT— C01–C12
- countryTEXT— US, DE, IN, UK, BR
- amountREAL
- statusTEXT— 'completed' or 'cancelled'
- ordered_atTEXT— YYYY-MM-DD HH:MM:SS
Pick a warehouse dialect above the editor. The engine is still SQLite; common syntax is rewritten before it runs.
SQLite cheat sheet
- Truncate to day
DATE(ordered_at) - Current date
DATE('now') - Conditional
CASE WHEN … THEN … ELSE … END - String aggregate
GROUP_CONCAT(col, ", ") - JSON field
json_extract(payload, '$.source') - Date difference
JULIANDAY(a) - JULIANDAY(b) - Filter a window
CTE, then WHERE rn = 1 - Median
ROW_NUMBER + COUNT(*) OVER ()
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